02x^2-X-0,125=0

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Solution for 02x^2-X-0,125=0 equation:



02x^2-x-0.125=0
We add all the numbers together, and all the variables
02x^2-1x-0.125=0
a = 02; b = -1; c = -0.125;
Δ = b2-4ac
Δ = -12-4·02·(-0.125)
Δ = 2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2}}{2*02}=\frac{1-\sqrt{2}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2}}{2*02}=\frac{1+\sqrt{2}}{4} $

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